AlexKontorovich/PrimeNumberTheoremAnd
Source indexedtheorem · leanprover/lean4:v4.32.0
ae_volume_of_contains_compl_singleton_zero
PrimeNumberTheoremAnd.MediumPNT · PrimeNumberTheoremAnd/MediumPNT.lean:1616 to 1643
Mathematical statement
Exact Lean statement
theorem ae_volume_of_contains_compl_singleton_zero
(s : Set ℝ)
(h : (univ : Set ℝ) \ {0} ⊆ s) :
s ∈ (MeasureTheory.ae volume)Complete declaration
Lean source
Full Lean sourceLean 4
theorem ae_volume_of_contains_compl_singleton_zero (s : Set ℝ) (h : (univ : Set ℝ) \ {0} ⊆ s) : s ∈ (MeasureTheory.ae volume) := by -- The key insight is that {0} has measure zero in ℝ have h_zero_null : volume ({0} : Set ℝ) = 0 := by exact volume_singleton -- Since s contains univ \ {0} = ℝ \ {0}, its complement is contained in {0} have h_compl_subset : sᶜ ⊆ {0} := by intro x hx -- If x is not in s, then x is not in ℝ \ {0} (since ℝ \ {0} is a subset of s) -- This means x = 0 by_contra h_not_zero have : x ∈ univ \ {0} := ⟨trivial, h_not_zero⟩ exact hx (h this) -- Therefore, volume(sᶜ) ≤ volume({0}) = 0 have h_compl_measure : volume sᶜ ≤ volume ({0} : Set ℝ) := measure_mono h_compl_subset -- So volume(sᶜ) = 0 have h_compl_zero : volume sᶜ = 0 := by rw [h_zero_null] at h_compl_measure exact le_antisymm h_compl_measure (by positivity) -- A set is in ae.sets iff its complement has measure zero rwa [mem_ae_iff]