AlexKontorovich/PrimeNumberTheoremAnd
Source indexedtheorem · leanprover/lean4:v4.32.0
Complex.continuousOn_digamma_of_re_ge_norm_le
PrimeNumberTheoremAnd.Mathlib.Analysis.SpecialFunctions.Gamma.DigammaSeries · PrimeNumberTheoremAnd/Mathlib/Analysis/SpecialFunctions/Gamma/DigammaSeries.lean:577 to 612
Source documentation
The digamma function is continuous on bounded closed substrips of the right half-plane.
Exact Lean statement
theorem continuousOn_digamma_of_re_ge_norm_le {a R : ℝ} (ha : 0 < a) (ha1 : a ≤ 1) :
ContinuousOn digamma ({z : ℂ | a ≤ z.re} ∩ {z : ℂ | ‖z‖ ≤ R})Complete declaration
Lean source
Full Lean sourceLean 4
theorem continuousOn_digamma_of_re_ge_norm_le {a R : ℝ} (ha : 0 < a) (ha1 : a ≤ 1) : ContinuousOn digamma ({z : ℂ | a ≤ z.re} ∩ {z : ℂ | ‖z‖ ≤ R}) := by set s : Set ℂ := {z : ℂ | a ≤ z.re} ∩ {z : ℂ | ‖z‖ ≤ R} have hu : Summable (fun m : ℕ => (R + 1) / (a * ((m : ℝ) + 1) ^ 2)) := by refine (summable_one_div_natCast_add_one_sq.mul_left ((R + 1) / a)).congr fun m => ?_ rw [mul_one_div, div_div] have hseries : ContinuousOn (fun z : ℂ => ∑' m : ℕ, (1 / ((m : ℂ) + 1) - 1 / ((m : ℂ) + z))) s := by refine continuousOn_tsum (f := fun m (z : ℂ) => 1 / ((m : ℂ) + 1) - 1 / ((m : ℂ) + z)) (u := fun m : ℕ => (R + 1) / (a * ((m : ℝ) + 1) ^ 2)) ?hf hu ?hbound · intro m have hden : ContinuousOn (fun z : ℂ => ((m : ℂ) + z)⁻¹) s := by refine (continuousOn_const.add continuousOn_id).inv₀ ?_ intro z hz hzero change (m : ℂ) + z = 0 at hzero have hza : a ≤ z.re := hz.1 have hzpos : 0 < (((m : ℂ) + z) : ℂ).re := by rw [add_re, natCast_re] have hm_nonneg : 0 ≤ (m : ℝ) := by positivity linarith [ha, hza, hm_nonneg] rw [hzero] at hzpos norm_num at hzpos simpa only [one_div] using continuousOn_const.fun_sub hden · intro m z hz have h := norm_inv_add_one_sub_inv_le ha ha1 hz.1 hz.2 m simpa [one_div, add_comm] using h exact (continuousOn_const.add hseries).congr fun z hz => by exact digamma_eq_tsum fun n hzn => by have hre := congrArg Complex.re hzn have hza : a ≤ z.re := hz.1 have hzpos : 0 < z.re := lt_of_lt_of_le ha hz.1 have hre' : z.re = -(n : ℝ) := by simpa using hre have hn : 0 ≤ (n : ℝ) := by positivity linarith