AlexKontorovich/PrimeNumberTheoremAnd
Source indexedtheorem · leanprover/lean4:v4.32.0
MobiusLemma.mobius_lemma_2_sub_1
PrimeNumberTheoremAnd.IEANTN.MobiusLemma · PrimeNumberTheoremAnd/IEANTN/MobiusLemma.lean:401 to 426
Source documentation
Since our sums start from , the sum is empty for .
Exact Lean statement
@[blueprint
"mobius-lemma-2-sub-1"
(title := "Mobius Lemma 2 - first step")
(statement := /--
For any $K \leq x$,
$$
\sum_{k\leq x} M\left(\sqrt{\frac{x}{k}}\right) = \sum_{k\leq K} M\left(\sqrt{\frac{x}{k}}\right)
+ \sum_{K < k\leq x+1} \int_{k-\frac{1}{2}}^{k+\frac{1}{2}}
M\left(\sqrt{\frac{x}{k}}\right) du.
$$
-/)
(proof := /-- This is just splitting the sum at $K$. -/)
(latexEnv := "sublemma")
(discussion := 528)]
theorem mobius_lemma_2_sub_1 (x : ℝ) (hx : x > 0) (K : ℕ) (hK : (K : ℝ) ≤ x) :
∑ k ∈ Ioc 0 ⌊x⌋₊, M (Real.sqrt (x / k)) = ∑ k ∈ range (K + 1), M (Real.sqrt (x / k)) +
∑ k ∈ Ico (K + 1) (⌊x⌋₊ + 2), ∫ _ in (k - 0.5)..(k + 0.5), (M (Real.sqrt (x / k)) : ℝ)Complete declaration
Lean source
Full Lean sourceLean 4
@[blueprint "mobius-lemma-2-sub-1" (title := "Mobius Lemma 2 - first step") (statement := /-- For any $K \leq x$, $$ \sum_{k\leq x} M\left(\sqrt{\frac{x}{k}}\right) = \sum_{k\leq K} M\left(\sqrt{\frac{x}{k}}\right) + \sum_{K < k\leq x+1} \int_{k-\frac{1}{2}}^{k+\frac{1}{2}} M\left(\sqrt{\frac{x}{k}}\right) du. $$ -/) (proof := /-- This is just splitting the sum at $K$. -/) (latexEnv := "sublemma") (discussion := 528)]theorem mobius_lemma_2_sub_1 (x : ℝ) (hx : x > 0) (K : ℕ) (hK : (K : ℝ) ≤ x) : ∑ k ∈ Ioc 0 ⌊x⌋₊, M (Real.sqrt (x / k)) = ∑ k ∈ range (K + 1), M (Real.sqrt (x / k)) + ∑ k ∈ Ico (K + 1) (⌊x⌋₊ + 2), ∫ _ in (k - 0.5)..(k + 0.5), (M (Real.sqrt (x / k)) : ℝ) := by norm_num [sum_Ico_eq_sub] rw [sum_range_add_sum_Ico] · erw [← Icc_succ_left_eq_Ioc, sum_Ico_eq_sub _] · norm_num [Finset.sum_range_succ, M] rw [Nat.floor_eq_zero.mpr] · norm_num · rw [div_lt_one (by positivity), sqrt_lt_sqrt_iff] <;> linarith [Nat.lt_floor_add_one x] · simp · linarith [Nat.le_floor hK]