All open problems
Source labels openChecked July 26, 2026

Erdős ProblemsCombinatorics

Erdős Problem 236

Let f(n)f(n) count the number of solutions to n=p+2kn=p+2^k for prime pp and k0k\geq 0. Show that f(n)=o(logn)f(n)=o(\log n).

Mathematical statement

Let f(n)f(n) count the number of solutions to n=p+2kn=p+2^k for prime pp and k0k\geq 0. Show that f(n)=o(logn)f(n)=o(\log n).

Statement source: Erdős Problems statement material

Statement terms: Source-specific

Source-specific terms. Therefore does not assert reuse rights beyond attributed display.

Statement artifacts, not proofs

These records expose exact Lean propositions and statement-only wrappers. Defining a proposition does not supply a proof of it. A placeholder-bearing target also contains no proof. Elaboration checks syntax and types; it does not certify that a formalization perfectly captures every nuance of the informal problem.

Pinned Lean formulation 1

erdos_236

Canonical source
Complete statement target, proof intentionally absentLean 4
theorem erdos_236: (fun n => (f n : )) =o[atTop] (fun n => Real.log (n : )) := by  sorry
Statement source
Formal Conjectures
Lean version
v4.27.0
Placeholder
Present; no proof artifact
Source evidence
Pinned source index
Fidelity review
Community formulation

References