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Mathoverflow 347178: Bounded Only

Let f:RnR,n2f : \mathbb R^n \to \mathbb R, n \geq 2 be a C1C^1 function. Does the equality supxRnf(x)=supxRnf(x+f(x))\sup_{x \in \mathbb R^n}f(x) = \sup_{x\in \mathbb R^n} f(x+\nabla f(x)) hold when both suprema are finite?

Mathematical statement

Let f:RnR,n2f : \mathbb R^n \to \mathbb R, n \geq 2 be a C1C^1 function. Does the equality supxRnf(x)=supxRnf(x+f(x))\sup_{x \in \mathbb R^n}f(x) = \sup_{x\in \mathbb R^n} f(x+\nabla f(x)) hold when both suprema are finite?

Statement source: MathOverflow statement material

Statement terms: CC-BY-SA-4.0

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Statement artifacts, not proofs

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Pinned Lean formulation 1

mathoverflow_347178.variants.bounded_only

Canonical source
Complete statement target, proof intentionally absentLean 4
theorem mathoverflow_347178.variants.bounded_only :    answer(sorry)  ᵉ (n  2) (f : ^n  ) (hf : ContDiff  1 f)        (h : BddAbove (range f)) (h' : BddAbove (range (fun x  f (x + gradient f x)))),        (⨆ x, f x) = ⨆ x, f (x + gradient f x) := by  sorry
Statement source
Formal Conjectures
Lean version
v4.27.0
Placeholder
Present; no proof artifact
Source evidence
Pinned source index
Fidelity review
Community formulation

References