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WikipediaNumber theory

Rudin's conjecture on squares in arithmetic progressions

Rudin's conjecture.* The maximal number of squares among the first NN terms of a non-trivial arithmetic progression grows at most like N\sqrt{N}: Q(N)=O(N).Q(N) = O(\sqrt{N}).

Mathematical statement

Rudin's conjecture.* The maximal number of squares among the first NN terms of a non-trivial arithmetic progression grows at most like N\sqrt{N}: Q(N)=O(N).Q(N) = O(\sqrt{N}).

Statement source: Wikipedia statement material

Statement terms: CC-BY-SA-4.0

Attributed source material. Reuse must follow the linked attribution and share-alike terms.

Statement artifacts, not proofs

These records expose exact Lean propositions and statement-only wrappers. Defining a proposition does not supply a proof of it. A placeholder-bearing target also contains no proof. Elaboration checks syntax and types; it does not certify that a formalization perfectly captures every nuance of the informal problem.

Pinned Lean formulation 1

rudins_conjecture

Canonical source
Complete statement target, proof intentionally absentLean 4
theorem rudins_conjecture :    (fun N :  => (Qmax N : )) =O[atTop] fun N :  => Real.sqrt N := by  sorry
Statement source
Formal Conjectures
Lean version
v4.27.0
Placeholder
Present; no proof artifact
Source evidence
Pinned source index
Fidelity review
Community formulation

References