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Open-problem statements, with their sources attached.

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Exponentials conjectures and theorems

The four exponential conjecture would imply that for any irrational number tt, at least one of the numbers 2t2^t and 3t3^t is transcendental.

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Source labels openWikipedia · Number theory

Feit-Thompson conjecture on primes

There are no distinct primes pp and qq such that qp1q1\frac{q^p - 1}{q - 1} divides pq1p1\frac{p^q - 1}{p - 1}

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Source labels openWikipedia · Number theory

Open questions about Fermat numbers

Are Fermat numbers composite for all n > 4?

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Source labels openWikipedia · Number theory

Open questions about Fermat numbers

Are there infinitely many Fermat primes?

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Source labels openWikipedia · Number theory

Open questions about Fermat numbers

Are there infinitely many composite Fermat numbers?

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Source labels openWikipedia · Number theory

Open questions about Fermat numbers

Are all Fermat numbers are square-free?

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Source labels openWikipedia · Number theory

Fermat-Catalan conjecture

The Fermat–Catalan conjecture states that the equation am+bn=cka^m + b^n = c^k has only finitely many solutions (a,b,c,m,n,k)(a,b,c,m,n,k) with distinct triplets of values (am,bn,ck)(a^m, b^n, c^k) where a,b,ca, b, c are positive coprime integers and m,n,km, n, k are positive integers satisfying 1m+1n+1k<1\frac 1 m + \frac 1 n + \frac 1 k < 1.

Source checked Jul 26, 20261 pinned Lean statementInspect problem
Source labels openWikipedia · Number theory

Fibonacci Primes

There are infinitely many Fibonacci primes, i.e., Fibonacci numbers that are prime It is also a barrier to defining a benchmark from this paper: https://arxiv.org/html/2505.13938v1 (see Figure 8).

Source checked Jul 26, 20261 pinned Lean statementInspect problem
Source labels openWikipedia · Number theory

Fibonacci Primes: Variant

There are infinitely many indices ii, such that the ii-th Fibonacci is prime.

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Source labels openWikipedia · Number theory

Firoozbakht's conjecture

Firoozbakht's conjecture* The inequality pn+1n+1<pnn\sqrt[n+1]{p_{n+1}} < \sqrt[n]{p_n} holds for all prime numbers pnp_n.

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Source labels openWikipedia · Number theory

Gauss circle problem

It is conjectured that the correct bound is

E(r)=O(r1/2+o(1)) |E(r)| = O\left(r^{1/2 + o(1)}\right)

[Ha59] Hardy, G. H. (1959). Ramanujan: Twelve Lectures on Subjects Suggested by His Life and Work(3rd ed.). New York: Chelsea Publishing Company. p. 67

See also https://arxiv.org/abs/2305.03549

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Source labels openWikipedia · Number theory

Gilbreath's conjecture

Gilbreath's conjecture* Gilbreath's conjecture states that every term in the sequence d0kd^k_0 for k>0k > 0 is equal to 1.

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Source labels openWikipedia · Number theory

Goldbach's conjecture

Can every even integer greater than 2 be written as the sum of two primes?

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Grimm's conjecture

Grimm's Conjecture* If n,n+1,,n+k1n, n+1, \dots, n+k-1 are all composite numbers, then there are kk distinct primes pip_i such that pip_i divides n+in + i for all 0ik10 \le i \le k-1.

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Source labels openWikipedia · Number theory

Grimm's conjecture

Grimm's Conjecture, weaker version* If n,n+1,,n+k1n, n+1, \dots, n+k-1 are all composite numbers, then their product has at least kk distinct prime divisors.

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Source labels openWikipedia · Number theory

Hall's conjecture

Original Hall's conjecture with exponent 1/21/2.

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Source labels openWikipedia · Number theory

Hall's conjecture

Weak form of Hall's conjecture: relax the exponent from 1/21/2 to 1/2ε1/2 - \varepsilon.

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Source labels openWikipedia · Number theory

First Hardy–Littlewood conjecture

Let P=(m1,,mk)P = (m_1, \dots, m_k) be a tuple of positive even integers. Let πP(n)\pi_P(n) denote the number of primes pnp\leq n such that (p,p+m1,,p+mk)(p, p + m_1, \dots, p + m_k) forms an admissible prime constellation. Let w(q;m1,,mk)w(q; m_1, \dots, m_k) denote the number of distinct residues of 0,m1,,mk0, m_1, \dots, m_k modulo qq, and let

CP=2kq primeq31w(q;m1,,mk)q(11q)k+1. C_P = 2 ^ k\prod_{\substack{q\ \text{prime} \\ q\geq 3}} \frac{1 - \frac{w(q; m_1, \dots, m_k)}{q}}{\left(1 - \frac{1}{q}\right)^{k+1}}.

Then

πP(n)CP2ndtlogk+1t. \pi_P(n)\sim C_P\int_2^n\frac{dt}{\log^{k+1}t}.
Source checked Jul 26, 20261 pinned Lean statementInspect problem
Source labels openWikipedia · Number theory

First Hardy–Littlewood conjecture

For integers x,y2x, y \geq 2,

π(x+y)π(x)+π(y), \pi(x + y) \leq \pi(x) + \pi(y),

where π(z)\pi(z) denotes the prime-counting function, giving the number of primes up to and including zz.

Source checked Jul 26, 20261 pinned Lean statementInspect problem