Dense Range of prod Algebra Map
IsDedekindDomain.HeightOneSpectrum.denseRange_of_prodAlgebraMap
Plain-language statement
If s is finite then K in dense in ∏_{v ∈ s} K_v.
Exact Lean statement
theorem denseRange_of_prodAlgebraMap {ι : Type*} [Finite ι]
{valuation : ι → HeightOneSpectrum A} (injective : Function.Injective valuation) :
DenseRange (algebraMap K ((i : ι) → (valuation i).adicCompletion K))Formal artifact
Lean source
theorem denseRange_of_prodAlgebraMap {ι : Type*} [Finite ι] {valuation : ι → HeightOneSpectrum A} (injective : Function.Injective valuation) : DenseRange (algebraMap K ((i : ι) → (valuation i).adicCompletion K)) := by rw [denseRange_iff_closure_range, Set.eq_univ_iff_forall] let S := Set.range (algebraMap K ((i : ι) → (valuation i).adicCompletion K)) -- We've already shown that the closure of `A` is `∏_{v ∈ s} 𝒪_v`, so -- the closure of `K` at least contains this set. have hint : Set.pi Set.univ (fun (i : ι) ↦ ((valuation i).adicCompletionIntegers K).carrier) ⊆ closure S := by rw [← closureAlgebraMapIntegers_eq_prodIntegers _ _ injective] apply closure_mono exact fun _ ⟨a, ha⟩ ↦ ⟨algebraMap A K a, ha⟩ -- Next, the closure of `K` is closed under multiplication by `K` because -- scalar multiplication by a constant is continuous. have hmul : ∀x, x ∈ closure S → ∀k : K, k • x ∈ closure S := by intro x h k let f := fun (z : (i : ι) → (valuation i).adicCompletion K) ↦ k • z have hf : ContinuousAt f x := Continuous.continuousAt (continuous_const_smul k) apply closure_mono _ <| mem_closure_image hf h rintro x ⟨_, ⟨z, rfl⟩, rfl⟩ use k • algebraMap K _ z ext i simp [Algebra.smul_def, f] -- Finally, `∏_{v ∈ s} K_v = K • ∏_{v ∈ s} 𝒪_v` intro x obtain ⟨k, y, hy, hx⟩ := adicCompletion.eq_mul_pi_adicCompletionIntegers K valuation x exact hx ▸ hmul y (hint hy) k- Project
- Fermat's Last Theorem
- License
- Apache-2.0
- Commit
- 8dd808888295
- Source
- FLT/DedekindDomain/AdicValuation.lean:434-460
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