Weierstrass equation
TateCurve.weierstrass_equation
Plain-language statement
The point (X(u,q), Y(u,q)) satisfies the Weierstrass equation y² + xy = x³ + a₄x + a₆ of the Tate curve, as an identity in ℚ(u)⟦q⟧.
Exact Lean statement
theorem weierstrass_equation : Y ^ 2 + X * Y = X ^ 3 + a₄ * X + a₆
Formal artifact
Lean source
theorem weierstrass_equation : Y ^ 2 + X * Y = X ^ 3 + a₄ * X + a₆ := by rw [← sub_eq_zero] refine eq_zero_of_forall_hasSum_zero _ {u : ℂ | Transcendental ℚ u ∧ 0 < ‖u‖ ∧ ‖u‖ < 1} transcendental_punctured_unit_disk_infinite fun u hu ↦ ⟨‖u‖, hu.2.1, fun q hq0 hqu ↦ ?_⟩ obtain ⟨htr, -, hu1⟩ := hu have hq1 : ‖q‖ < 1 := hqu.trans hu1 have hX := hasSum_X_eval htr hq0 hqu hu1 have hY := hasSum_Y_eval htr hq0 hqu hu1 have hY2 : HasSum (fun n : ℕ ↦ evalAt u ((PowerSeries.coeff n) (Y ^ 2)) * q ^ n) (YAn u q ^ 2) := by simpa [pow_two] using hasSum_evalAt_mul htr hY hY have hX3 : HasSum (fun n : ℕ ↦ evalAt u ((PowerSeries.coeff n) (X ^ 3)) * q ^ n) (XAn u q ^ 3) := by have hX2 : HasSum (fun n : ℕ ↦ evalAt u ((PowerSeries.coeff n) (X ^ 2)) * q ^ n) (XAn u q ^ 2) := by simpa [pow_two] using hasSum_evalAt_mul htr hX hX simpa [pow_succ, pow_two, mul_assoc] using hasSum_evalAt_mul htr hX2 hX have hsum := hasSum_evalAt_sub htr (hasSum_evalAt_add htr hY2 (hasSum_evalAt_mul htr hX hY)) (hasSum_evalAt_add htr (hasSum_evalAt_add htr hX3 (hasSum_evalAt_mul htr (hasSum_a₄_eval u hq1) hX)) (hasSum_a₆_eval u hq1)) convert hsum using 1 rw [analytic_weierstrass hq0 hqu hu1] ring- Project
- Fermat's Last Theorem
- License
- Apache-2.0
- Commit
- 8dd808888295
- Source
- FLT/KnownIn1980s/EllipticCurves/TateCurveConstruction.lean:1527-1549
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