Ultra Product surjective of bdd Above card
UltraProduct.surjective_of_bddAbove_card
Plain-language statement
Let Rβ be a topological ring, topologically of finite type (over β€). Consider a family of (cardinality) finite rings R i with the discrete topology whose cardinalites are unifomly bounded. Given a family of continuous surjective ring homs f i : R β+* R i, the lift R β+* π°(Rα΅’) is also surjective.
Exact Lean statement
lemma UltraProduct.surjective_of_bddAbove_card
[TopologicalSpace Rβ]
[IsTopologicalRing Rβ]
[Algebra.TopologicallyFG β€ Rβ]
[β i, TopologicalSpace (R i)]
[β i, IsTopologicalRing (R i)]
[β i, T2Space (R i)] (F : Ultrafilter ΞΉ)
(N : β) (H : βαΆ i in F, Finite (R i) β§ Nat.card (R i) < N)
(f : β i, Rβ β+* R i) (hf : βαΆ i in F, Continuous (f i))
(hf' : βαΆ i in F, Function.Surjective (f i)) :
Function.Surjective ((Ο R F).comp (RingHom.pi f))Formal artifact
Lean source
lemma UltraProduct.surjective_of_bddAbove_card [TopologicalSpace Rβ] [IsTopologicalRing Rβ] [Algebra.TopologicallyFG β€ Rβ] [β i, TopologicalSpace (R i)] [β i, IsTopologicalRing (R i)] [β i, T2Space (R i)] (F : Ultrafilter ΞΉ) (N : β) (H : βαΆ i in F, Finite (R i) β§ Nat.card (R i) < N) (f : β i, Rβ β+* R i) (hf : βαΆ i in F, Continuous (f i)) (hf' : βαΆ i in F, Function.Surjective (f i)) : Function.Surjective ((Ο R F).comp (RingHom.pi f)) := by obtain β¨i, β¨e, heβ©, hfβ© := ((UltraProduct.exists_ringEquiv_of_bddAbove_card F N H f hf).and hf').exists have : e.symm.toRingHom.comp (f i) = (Ο R F).comp (RingHom.pi f) := by rw [β he, β RingHom.comp_assoc]; simp rw [β this] exact e.symm.surjective.comp hf- Project
- Fermat's Last Theorem
- License
- Apache-2.0
- Commit
- 8dd808888295
- Source
- FLT/Patching/Ultraproduct.lean:429-445
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