Integral Model base Change map
WeierstrassCurve.integralModel_baseChange_map
Plain-language statement
The integral model of the base change is the base change of the integral model. Both sides are lifts of E.baseChange l along the injective map ๐ช[l] โ l (injectivity from IsFractionRing), and lifts along an injective map are unique: compare coefficientwise via integralModel_aโ_eq on both sides and the commuting square algebraMap_integerMap. (O...
Exact Lean statement
theorem integralModel_baseChange_map [IsIntegral ๐ช[k] E] :
integralModel ๐ช[l] (E.baseChange l) =
(integralModel ๐ช[k] E).map (integerMap k l)Formal artifact
Lean source
theorem integralModel_baseChange_map [IsIntegral ๐ช[k] E] : integralModel ๐ช[l] (E.baseChange l) = (integralModel ๐ช[k] E).map (integerMap k l) := by -- both sides base change to `E.baseChange l`; `๐ช[l] โ l` is injective, so `map` is refine map_injective (f := algebraMap ๐ช[l] l) (IsFractionRing.injective ๐ช[l] l) ?_ change (integralModel ๐ช[l] (E.baseChange l)).map (algebraMap ๐ช[l] l) = ((integralModel ๐ช[k] E).map (integerMap k l)).map (algebraMap ๐ช[l] l) have hcomp : (algebraMap ๐ช[l] l).comp (integerMap k l) = (algebraMap k l).comp (algebraMap ๐ช[k] k) := by ext x; simpa using algebraMap_integerMap k l x rw [map_map, hcomp, โ map_map, show (integralModel ๐ช[k] E).map (algebraMap ๐ช[k] k) = E from baseChange_integralModel_eq ๐ช[k] E] exact baseChange_integralModel_eq ๐ช[l] (E.baseChange l)- Project
- Fermat's Last Theorem
- License
- Apache-2.0
- Commit
- 8dd808888295
- Source
- FLT/KnownIn1980s/EllipticCurves/ReductionBaseChange.lean:277-289
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