Integral indicator tail even
Heat.integral_indicator_tail_even
Plain-language statement
For even functions, the two-sided tail integral equals twice the one-sided integral.
Exact Lean statement
lemma integral_indicator_tail_even {f : ℝ → ℝ} {R : ℝ} (hR : 0 < R)
(heven : ∀ x, f (-x) = f x)
(hint : IntegrableOn f (Set.Ici R)) :
∫ z, Set.indicator {z : ℝ | R ≤ |z|} f z
= 2 * ∫ z in Set.Ici R, f zFormal artifact
Lean source
lemma integral_indicator_tail_even {f : ℝ → ℝ} {R : ℝ} (hR : 0 < R) (heven : ∀ x, f (-x) = f x) (hint : IntegrableOn f (Set.Ici R)) : ∫ z, Set.indicator {z : ℝ | R ≤ |z|} f z = 2 * ∫ z in Set.Ici R, f z := by -- Split {z | R ≤ |z|} into two parts: (-∞, -R] ∪ [R, ∞) have h_split : {z : ℝ | R ≤ |z|} = Set.Iic (-R) ∪ Set.Ici R := by ext z simp only [Set.mem_setOf, Set.mem_union, Set.mem_Iic, Set.mem_Ici] constructor · intro h by_cases hz : z < 0 · left simp [abs_of_neg hz] at h linarith · right push_neg at hz simp [abs_of_nonneg hz] at h exact h · intro h cases h with | inl h => simp [abs_of_nonpos (by linarith : z ≤ 0)]; linarith | inr h => simp [abs_of_nonneg (by linarith : 0 ≤ z)]; exact h have h_disj : Disjoint (Set.Iic (-R)) (Set.Ici R) := by rw [Set.disjoint_iff] intro z hz simp only [Set.mem_inter_iff, Set.mem_Iic, Set.mem_Ici] at hz obtain ⟨h1, h2⟩ := hz linarith rw [h_split, Set.indicator_union_of_disjoint h_disj] rw [integral_add] swap; · -- integrability on Iic (-R) have h_int_left : IntegrableOn f (Set.Iic (-R)) := by rw [← Measure.map_neg_eq_self (volume : Measure ℝ)] let m : MeasurableEmbedding (fun x : ℝ => -x) := (Homeomorph.neg ℝ).measurableEmbedding rw [m.integrableOn_map_iff] simp_rw [Function.comp_def, Set.neg_preimage, Set.neg_Iic, neg_neg] convert hint using 2 aesop rw [integrable_indicator_iff measurableSet_Iic] exact h_int_left swap; · rw [integrable_indicator_iff measurableSet_Ici] exact hint have h_left_eq_right : ∫ z, Set.indicator (Set.Iic (-R)) f z = ∫ z, Set.indicator (Set.Ici R) f z := by rw [integral_indicator measurableSet_Iic] rw [integral_indicator measurableSet_Ici] -- Strategy: show ∫_{Iic(-R)} f = ∫_{Ici R} f using negation and evenness have : ∫ x in Set.Iic (-R), f x = ∫ x in Set.Ici R, f (-x) := by calc ∫ x in Set.Iic (-R), f x = ∫ x in Set.Ioi R, f (-x) := by convert integral_comp_neg_Iic (c := -R) f using 2 aesop aesop aesop _ = ∫ x in Set.Ici R, f (-x) := by rw [← integral_Ici_eq_integral_Ioi'] aesop rw [this] apply setIntegral_congr_ae measurableSet_Ici filter_upwards with z hz exact heven z rw [h_left_eq_right, integral_indicator measurableSet_Ici, ← two_mul]- Project
- PDE
- License
- Apache-2.0
- Commit
- 0ab5d79a0d7a
- Source
- PDE/Basics/Heat/HeatSolutionProperty.lean:226-294
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