Beaver Math Olympiad (BMO)
Let and be two sequences such that and
(a_n - \lfloor b_n/2 \rfloor - 3, 3 \lfloor (b_n+1)/2 \rfloor + 6) & \text{if } a_n > \lfloor b_n/2 \rfloor \\ (3 a_n + 5, b_n - 2 a_n) & \text{if } a_n \le \lfloor b_n/2 \rfloor \end{cases}$$ for all positive integers $n$. Does there exist a positive integer $i$ such that $a_i = \lfloor b_i/2 \rfloor + 1$? [BMO#8](https://wiki.bbchallenge.org/wiki/Beaver_Math_Olympiad#8._1RB0LD_0RC1RB_0RD0RA_1LE0RD_1LF---_0LA1LA_(bbch)) is equivalent to asking whether the 6-state Turing machine [`1RB0LD_0RC1RB_0RD0RA_1LE0RD_1LF---_0LA1LA`](https://wiki.bbchallenge.org/wiki/1RB0LD_0RC1RB_0RD0RA_1LE0RD_1LF---_0LA1LA) halts or not. There is presently no consensus on whether the machine halts or not, hence the problem is formulated using `answer(sorry) ↔`.