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Source labels openErdős Problems · Mathematical logic

Erdős Problem 1176

Let GG be a graph with chromatic number 1\aleph_1. Is it true that there is a colouring of the edges with 1\aleph_1 many colours such that, in any countable colouring of the vertices, there exists a vertex colour containing all edge colours?

A problem of Erdős, Galvin, and Hajnal. The consistency of this was proved by Hajnal and Komjáth.

Source checked Jul 26, 20261 pinned Lean statementInspect problem
Source labels openarXiv · Combinatorics

Independent Domination of Regular Graphs, Conjecture 1.6

Conjecture 1.6 (Even case).* For a nonempty isolate-free graph GG on nn vertices, if DD is even, then (D+2)2i(G)(D2+4)n(D + 2)^2 \cdot i(G) \leq (D^2 + 4) \cdot n.

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Source labels openErdős Problems · Mathematical logic

Erdős Problem 598

Erdős Problem 598:* Let mm be an infinite cardinal and κ\kappa be the successor cardinal of 202^{\aleph_0}. Can one colour the countable subsets of mm using κ\kappa many colours so that every XmX \subseteq m with X=κ|X| = \kappa contains subsets of all possible colours?

Source checked Jul 26, 20261 pinned Lean statementInspect problem
Source labels openarXiv · Combinatorics

Independent Domination of Regular Graphs, Conjecture 1.6

Conjecture 1.6 (Odd case).* For a nonempty isolate-free graph GG on nn vertices, if DD is odd, then (D+1)(D+3)i(G)(D2+3)n(D + 1)(D + 3) \cdot i(G) \leq (D^2 + 3) \cdot n.

Source checked Jul 26, 20261 pinned Lean statementInspect problem
Source labels openErdős Problems · Mathematical logic

Erdős Problem 602

Does every almost-disjoint family of countably infinite sets whose pairwise intersections all have size ≠ 1 have Property B?

Formally: let α be any type, let (A_i)_{i ∈ I} be a family of countably infinite subsets of α such that for all i ≠ j, the intersection A_i ∩ A_j is finite and |A_i ∩ A_j| ≠ 1. Does there exist a 2-colouring f : α → Fin 2 such that no A_i is monochromatic?

This is an open question about Property B for almost-disjoint families with a forbidden intersection size of 1. Note:* This generalises the formulation in which the ground set is . Since every countably infinite set is in bijection with , the two formulations are equivalent, but working over an arbitrary ground type makes the statement apply immediately to, e.g., almost-disjoint families of countable subsets of an uncountable space.

Source checked Jul 26, 20261 pinned Lean statementInspect problem
Source labels openarXiv · Combinatorics

Digit $2$ in base $3$ representation of $2^n$

For n>8n > 8, 2n2^n is not the the sum of distinct powers of 33. Expressed here in terms of the base 33 digits of nn.

This conjecture is equivalent to the halting of a 1515-state 22-symbol Turing Machine.

TODO(lezeau): Formalize the Turing Machine version of this problem.

Source: Hardness of Busy Beaver Value BB(15): https://link.springer.com/chapter/10.1007/978-3-031-72621-7_9 This is also https://arxiv.org/abs/2107.12475.

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Source labels openErdős Problems · Combinatorics

Erdős Problem 1

If A{1,...,N}A\subseteq\{1, ..., N\} with A=n|A| = n is such that the subset sums aSa\sum_{a\in S}a are distinct for all SAS\subseteq A then

N2n. N \gg 2 ^ n.
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Source labels openErdős Problems · Combinatorics

Erdős Problem 1: Real

A generalisation of the problem to sets A(0,N]A \subseteq (0, N] of real numbers, such that the subset sums all differ by at least 11 is proposed in [Er73] and [ErGr80].

[Er73] Erdős, P., Problems and results on combinatorial number theory. A survey of combinatorial theory (Proc. Internat. Sympos., Colorado State Univ., Fort Collins, Colo., 1971) (1973), 117-138.

[ErGr80] Erdős, P. and Graham, R., Old and new problems and results in combinatorial number theory. Monographies de L'Enseignement Mathematique (1980).

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Source labels openErdős Problems · Combinatorics

Erdős Problem 10

Is there some kk such that every integer is the sum of a prime and at most kk powers of 22?

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Source labels openErdős Problems · Combinatorics

Erdős Problem 10: Granville Soundararajan Odd

Granville and Soundararajan [GrSo98] have conjectured that at most 33 powers of 22 suffice for all odd integers, and hence at most 44 powers of 22 suffice for all even integers.

Ref: Granville, A. and Soundararajan, K., A Binary Additive Problem of Erdős and the Order of 22 mod p2p^2

Source checked Jul 26, 20261 pinned Lean statementInspect problem
Source labels openErdős Problems · Combinatorics

Erdős Problem 10: Grechuk

Bogdan Grechuk has observed that 11171751461117175146 is not the sum of a prime and at most 33 powers of 22, and pointed out that parity considerations, coupled with the fact that there are many integers not the sum of a prime and 22 powers of 22 suggest that there exist infinitely many even integers which are not the sum of a prime and at most 33 powers of 22).

Source checked Jul 26, 20261 pinned Lean statementInspect problem
Source labels openErdős Problems · Combinatorics

Erdős Problem 1068

Does every graph with chromatic number 1\aleph_1 contain a countable subgraph which is infinitely connected?

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Source labels openErdős Problems · Combinatorics

Erdős Problem 108

For every r ≥ 4 and k ≥ 2 is there some finite f(k,r) such that every graph of chromatic number ≥ f(k,r) contains a subgraph of girth ≥ r and chromatic number ≥ k?

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Source labels openErdős Problems · Combinatorics

Erdős Problem 1093: I

Are there infinitely many binomial coefficients with deficiency 1?

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Source labels openErdős Problems · Combinatorics

Erdős Problem 1093: Ii

Are there only finitely many binomial coefficients with deficiency > 1?

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Source labels openErdős Problems · Combinatorics

Erdős Problem 1145

Let A={1a1<a2<}A=\{1\leq a_1 < a_2 < \cdots\} and B={1b1<b2<}B=\{1\leq b_1 < b_2 < \cdots\} be sets of integers with an/bn1a_n/b_n\to 1.

If A+BA+B contains all sufficiently large positive integers then is it true that lim sup1A1B(n)=\limsup 1_A\ast 1_B(n)=\infty?

A conjecture of Erdős and Sárközy.

Source checked Jul 26, 20261 pinned Lean statementInspect problem
Source labels openErdős Problems · Combinatorics

Erdős Problem 1167

Erdős Problem 1167.* Let r2r \geq 2 be finite, γ2\gamma \geq 2, and λ\lambda be an infinite cardinal. Let κα\kappa_\alpha be cardinals for all α<γ\alpha < \gamma. Is it true that 2λ(κα+1)α<γr+12^\lambda \to (\kappa_\alpha + 1)_{\alpha < \gamma}^{r+1} implies λ(κα)α<γr?\lambda \to (\kappa_\alpha)_{\alpha < \gamma}^r? Here ++ means cardinal addition, so that κα+1=κα\kappa_\alpha + 1 = \kappa_\alpha if κα\kappa_\alpha is infinite.

A problem of Erdős, Hajnal, and Rado.

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Source labels openErdős Problems · Combinatorics

Erdős Problem 1167

Finite-target case.* When all κα\kappa_\alpha are finite, κα+1\kappa_\alpha + 1 is the ordinary natural-number successor. Special case of erdos_1167.

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Source labels openErdős Problems · Combinatorics

Erdős Problem 1167

Binary-color case.* The γ=2\gamma = 2 specialization (two color classes).

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