Mellin Convolution Symmetric
MellinConvolutionSymmetric
Plain-language statement
Mellin convolution is commutative at positive arguments. For functions or and every , where .
Exact Lean statement
@[blueprint
(title := "MellinConvolutionSymmetric")
(statement := /--
Let $f$ and $g$ be functions from $\mathbb{R}_{>0}$ to $\mathbb{R}$ or $\mathbb{C}$, for $x\neq0$,
$$
(f\ast g)(x)=(g\ast f)(x)
.
$$
-/)
(proof := /--
By Definition \ref{MellinConvolution},
$$
(f\ast g)(x) = \int_0^\infty f(y)g(x/y)\frac{dy}{y}
$$
in which we change variables to $z=x/y$:
$$
(f\ast g)(x) = \int_0^\infty f(x/z)g(z)\frac{dz}{z}
=(g\ast f)(x)
.
$$
-/)
(latexEnv := "lemma")]
lemma MellinConvolutionSymmetric (f g : ℝ → 𝕂) {x : ℝ} (xpos : 0 < x) :
MellinConvolution f g x = MellinConvolution g f xFormal artifact
Lean source
@[blueprint (title := "MellinConvolutionSymmetric") (statement := /-- Let $f$ and $g$ be functions from $\mathbb{R}_{>0}$ to $\mathbb{R}$ or $\mathbb{C}$, for $x\neq0$, $$ (f\ast g)(x)=(g\ast f)(x) . $$ -/) (proof := /-- By Definition \ref{MellinConvolution}, $$ (f\ast g)(x) = \int_0^\infty f(y)g(x/y)\frac{dy}{y} $$ in which we change variables to $z=x/y$: $$ (f\ast g)(x) = \int_0^\infty f(x/z)g(z)\frac{dz}{z} =(g\ast f)(x) . $$ -/) (latexEnv := "lemma")]lemma MellinConvolutionSymmetric (f g : ℝ → 𝕂) {x : ℝ} (xpos : 0 < x) : MellinConvolution f g x = MellinConvolution g f x := by unfold MellinConvolution calc _ = ∫ y in Ioi 0, f (y * x) * g (1 / y) / y := ?_ _ = _ := ?_ · rw [← integral_comp_mul_right_I0i_haar (fun y ↦ f y * g (x / y)) xpos] simp [div_mul_cancel_right₀ <| ne_of_gt xpos] · convert (integral_comp_inv_I0i_haar fun y ↦ f (y * x) * g (1 / y)).symm using 3 rw [one_div_one_div, mul_comm, mul_comm_div, one_mul]- Project
- Prime Number Theorem and More
- License
- Apache-2.0
- Commit
- a93551347dce
- Source
- PrimeNumberTheoremAnd/MellinCalculus.lean:293-324
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