Rectangle Integral HSplit
RectangleIntegralHSplit
Plain-language statement
A vertical splitting identity for rectangular contour integrals. Under integrability of along the two horizontal sides, splitting the rectangle with real coordinates from to at gives The two integrals over the shared vertical side cancel.
Exact Lean statement
lemma RectangleIntegralHSplit {a x₀ x₁ y₀ y₁ : ℝ}
(f_int_x₀_a_bot : IntervalIntegrable (fun x => f (↑x + ↑y₀ * I)) volume x₀ a)
(f_int_a_x₁_bot : IntervalIntegrable (fun x => f (↑x + ↑y₀ * I)) volume a x₁)
(f_int_x₀_a_top : IntervalIntegrable (fun x => f (↑x + ↑y₁ * I)) volume x₀ a)
(f_int_a_x₁_top : IntervalIntegrable (fun x => f (↑x + ↑y₁ * I)) volume a x₁) :
RectangleIntegral f (x₀ + y₀ * I) (x₁ + y₁ * I) =
RectangleIntegral f (x₀ + y₀ * I) (a + y₁ * I) +
RectangleIntegral f (a + y₀ * I) (x₁ + y₁ * I)Formal artifact
Lean source
lemma RectangleIntegralHSplit {a x₀ x₁ y₀ y₁ : ℝ} (f_int_x₀_a_bot : IntervalIntegrable (fun x => f (↑x + ↑y₀ * I)) volume x₀ a) (f_int_a_x₁_bot : IntervalIntegrable (fun x => f (↑x + ↑y₀ * I)) volume a x₁) (f_int_x₀_a_top : IntervalIntegrable (fun x => f (↑x + ↑y₁ * I)) volume x₀ a) (f_int_a_x₁_top : IntervalIntegrable (fun x => f (↑x + ↑y₁ * I)) volume a x₁) : RectangleIntegral f (x₀ + y₀ * I) (x₁ + y₁ * I) = RectangleIntegral f (x₀ + y₀ * I) (a + y₁ * I) + RectangleIntegral f (a + y₀ * I) (x₁ + y₁ * I) := by dsimp [RectangleIntegral, HIntegral, VIntegral] simp only [Complex.mul_re, Complex.mul_im, Complex.ofReal_re, Complex.ofReal_im, Complex.I_re, Complex.I_im, mul_one, mul_zero, add_zero, zero_add, sub_self] have h₁ := integral_add_adjacent_intervals f_int_x₀_a_bot f_int_a_x₁_bot have h₂ := integral_add_adjacent_intervals f_int_x₀_a_top f_int_a_x₁_top have h₁' : (∫ (x : ℝ) in x₀..a, f (↑x + ↑y₀ * I)) + ∫ (x : ℝ) in a..x₁, f (↑y₀ * I + ↑x) = ∫ (x : ℝ) in x₀..x₁, f (↑x + ↑y₀ * I) := by simpa [add_comm] using h₁ have h₂' : (∫ (x : ℝ) in x₀..a, f (↑x + ↑y₁ * I)) + ∫ (x : ℝ) in a..x₁, f (↑y₁ * I + ↑x) = ∫ (x : ℝ) in x₀..x₁, f (↑x + ↑y₁ * I) := by simpa [add_comm] using h₂ rw [← h₁', ← h₂'] have hcomm₁ : ∫ (x : ℝ) in a..x₁, f (↑y₀ * I + ↑x) = ∫ (x : ℝ) in a..x₁, f (↑x + ↑y₀ * I) := by apply intervalIntegral.integral_congr intro x _ exact congrArg f (by ring) have hcomm₂ : ∫ (x : ℝ) in a..x₁, f (↑y₁ * I + ↑x) = ∫ (x : ℝ) in a..x₁, f (↑x + ↑y₁ * I) := by apply intervalIntegral.integral_congr intro x _ exact congrArg f (by ring) rw [hcomm₁, hcomm₂] abel- Project
- Prime Number Theorem and More
- License
- Apache-2.0
- Commit
- a93551347dce
- Source
- PrimeNumberTheoremAnd/ResidueCalcOnRectangles.lean:256-293
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