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Project-declaredLean 4.32.0 · mathlib@81a5d257c8e4

Zeta Box Eval

ZetaBoxEval

Plain-language statement

For a continuously differentiable smoothing function supported in [1/2,2][1/2,2] and normalized by 0ν(x)dx/x=1\int_0^\infty \nu(x)\,dx/x=1, the Mellin factor of the smoothed cutoff at s=1s=1 is 1+O(ε)1+O(\varepsilon). Precisely, there is a constant CC such that, for every sufficiently small ε>0\varepsilon>0 and every X0X\ge0, M(1ε~)(1)XXCεX.\left|\mathcal M(\widetilde{1_\varepsilon})(1)X-X\right|\le C\varepsilon X.

Exact Lean statement

@[blueprint
  (title := "ZetaBoxEval")
  (statement := /--
  For all $\epsilon > 0$ sufficiently close to $0$, the rectangle integral over $[1-\delta,2] \times_{ℂ} [-T,T]$ of the integrand in
  $\psi_{\epsilon}$ is
  $$
  \frac{X^{1}}{1}\mathcal{M}(\widetilde{1_{\epsilon}})(1)
  = X(1+O(\epsilon))
  ,$$
  where the implicit constant is independent of $X$.
  -/)
  (proof := /-- Unfold the definitions and apply Lemma \ref{MellinOfSmooth1c}. -/)]
theorem ZetaBoxEval {SmoothingF : ℝ → ℝ}
    (suppSmoothingF : Function.support SmoothingF ⊆ Icc (1 / 2) 2)
    (mass_one : ∫ x in Ioi 0, SmoothingF x / x = 1)
    (ContDiffSmoothingF : ContDiff ℝ 1 SmoothingF) :
    ∃ C, ∀ᶠ ε in (nhdsWithin 0 (Ioi 0)), ∀ X : ℝ, 0 ≤ X →
    ‖𝓜 (fun x ↦ (Smooth1 SmoothingF ε x : ℂ)) 1 * X - X‖ ≤ C * ε * X

Formal artifact

Lean source

Canonical source
Full Lean sourceLean 4
@[blueprint  (title := "ZetaBoxEval")  (statement := /--  For all $\epsilon > 0$ sufficiently close to $0$, the rectangle integral over $[1-\delta,2] \times_{ℂ} [-T,T]$ of the integrand in  $\psi_{\epsilon}$ is  $$  \frac{X^{1}}{1}\mathcal{M}(\widetilde{1_{\epsilon}})(1)  = X(1+O(\epsilon))  ,$$  where the implicit constant is independent of $X$.  -/)  (proof := /-- Unfold the definitions and apply Lemma \ref{MellinOfSmooth1c}. -/)]theorem ZetaBoxEval {SmoothingF :   }    (suppSmoothingF : Function.support SmoothingF  Icc (1 / 2) 2)    (mass_one : ∫ x in Ioi 0, SmoothingF x / x = 1)    (ContDiffSmoothingF : ContDiff  1 SmoothingF) :     C, ᶠ ε in (nhdsWithin 0 (Ioi 0)),  X : , 0  X     ‖𝓜 (fun x  (Smooth1 SmoothingF ε x : ℂ)) 1 * X - X‖  C * ε * X := by  have := MellinOfSmooth1c ContDiffSmoothingF suppSmoothingF mass_one  clear suppSmoothingF mass_one ContDiffSmoothingF  rw[Asymptotics.isBigO_iff] at this  obtain C, hC := this  use C  have εpos : ᶠ (ε : ) in nhdsWithin 0 (Ioi 0), ε > 0 :=    eventually_mem_of_tendsto_nhdsWithin fun ⦃U⦄ hU  hU  filter_upwards [hC, εpos] with ε hC εpos  rw[id_eq, norm_of_nonneg (le_of_lt εpos)] at hC  intro X Xnne  nth_rw 2 [ one_mul (X : ℂ)]  rw[ sub_mul, norm_mul, norm_real, norm_of_nonneg Xnne]  exact mul_le_mul_of_nonneg_right hC Xnne
Project
Prime Number Theorem and More
License
Apache-2.0
Commit
a93551347dce
Source
PrimeNumberTheoremAnd/MediumPNT.lean:1569-1599

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Project-declaredLean 4.32.0

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