Ker le trace Right
ker_le_traceRight
Plain-language statement
The kernel condition σ.M.ker ≤ ρ.M.ker is preserved under partial trace. This follows because supp(ρ) ⊆ supp(σ) implies supp(Tr_B ρ) ⊆ supp(Tr_B σ): if v ∈ supp(Tr_B ρ), then ⟨v, (Tr_B ρ) v⟩ > 0, so for some basis vector e_b we have v ⊗ e_b ∈ supp(ρ) ⊆ supp(σ), hence ⟨v, (Tr_B σ) v⟩ ≥ ⟨v ⊗ e_b, σ (v ⊗ e_b)⟩ > 0.
Source project: quantumInfo
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